Question 1. The derivative of
function f(x)=2cos(3x-1)sin2x
is |
a) f′(x)=4sin(3x-1)sin2x-6cos2xcos(3x-1) |
b) f′(x)=-4sin(3x-1)sin2x+6cos2xcos(3x-1) |
c) f′(x)=6sin(3x-1)sin2x-4cos2xcos(3x-1) |
d) f′(x)=sin(3x-1)sin2x+cos2xcos(3x-1) |
e) f′(x)=-6sin(3x-1)sin2x+4cos2xcos(3x-1) |